∂u/∂t - β0 y v + g´ ∂h/∂x= τx/ρH
∂v/∂t + β0 y u + g´ ∂h/∂y= τy/ρH
∂h/∂t + H( ∂u/∂x + ∂v/∂y) = -A h
H = 150 m ;
c = 2.9 m/s
Domain: 124E-80W, 30S-30N
where the atmospheric coupling comes in the τx term,
making it dependent on the depth at the equator
in the east, h0:
τx = (k/ε) tanh(εh0)
exp(-(μ/2)y2/L2) g(x) ;
τy = 0
where L is the equatorial length scale, L2=c/β, and